Cold Rolling 1100/1050/1020/1060 Aluminum Coils For Decoration

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China main port
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TT OR LC
Min Order Qty:
5 m.t.
Supply Capability:
600 m.t./month

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Item specifice:

Grade: 1000 Series,3000 Series,5000 Series Surface Treatment: Mill Finish Shape: Flat
Temper: O-H112,Hard,Half Hard Application: Decorations,Door & Window Thickness: 0.08-8mm
Width: 280MM -1500MM Outer Diameter: 500 MM Packaging: Wooden pallet

Product Description:

Cold Rolling 1100/1050/1020/1060 Aluminum Coils For Decoration

Temper: h14,h16,h18,h22,h24,h26,h32,o/f

Thickness: o.o3mm-3.0mm

Width: 30mm-1700mm

Coating: pe(polyester),pvdf,epoxy

Painting thickness: standard 16-25 mic, max 40 mic

Color: according to ral colors or customer's samples

Packaging & Delivery


Packaging Details:Coil ID :508MM
Coil Weight : about 2.5 tons or as per customers requirement
Packing ; In Export Sea worhty wooden pallets
Eye to wall or Eye to Sky
One container can be loaded about 20 mts
Delivery Detail:within 25 days after receiving L/C deposit


Cold Rolling 1100/1050/1020/1060 Aluminum Coils For Decoration

Cold Rolling 1100/1050/1020/1060 Aluminum Coils For Decoration


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Q:mass of individual aluminum atom?
answer is 0.47/107 so each atom weighs 0.004392523364485981308411214953271g that can be rounded to whatever decimal places you want.
Q:Is my volvo S70 bumper aluminum or stainless steel?
Aluminum, stainless is too expensive and not ductile enough to be made into bumpers, especially of that complexity. As far as the magnetism, the magnet would only stick to low nickel stainless and its not likely that they would use 308 on a consumer vehicle.
Q:Aluminum plate 90 degree bending, why cracking?
Cracking of 90 degree bending of aluminium plate:1 bend radius is too small2, more impurities aluminum plate
Q:Which kind of material does aluminum sheet(aluminum oxide) belong to?
it's metal and belongs to hardware
Q:a sample of aluminum chloride (AlCI3) has a mass of 37.2 g.?
You have to remember Avogadro's number: 6.02 x 10^23 Read about it in your text book. It is the number of molecules of any atom that make up 1 mole. 1 mole of a molecule is equal to it's atomic weight in grams. So, the atomic weight of aluminum is 26.9. So, 26.9 grams of aluminum contains exactly 6.02 x 10^23 molecules of aluminum (or 1 mole). What's the molecular weight of aluminum chloride? Well, 26.9 + 3(35.5) = 133.4 the 35.5 is the molecular weight of chloride and there are 3 of them. So, 133.4 grams of aluminum chloride would be 6.02 x 10^23 molecules. We only have 37.2 g. 37.2 g/ 133.4 g per mole = 0.279 moles. 0.279 moles x (6.02 x 10^23 molecules/mole) = 1.68 x 10^23 molecules of aluminum chloride. So, since there is one aluminum per molecule, you have your answer. Just multiply by three to find out how many molecules of chloride are present. Finally, if 133.4g = 6.02 x 10^23 molecules, then 1 molecule = 133.4 / 6.02x10^23 = 22.16 x 10^-23 or 2.216 x 10^-22 Make sure that the periodic table you use for class has the same values (some tables are more simplified then others). Also, make sure that you use the correct number of scientific digits when calculating your answer.
Q:Why is it good to recycle aluminium?
Where aluminium is the third most common element on the planet (after oxygen and hydrogen), it is also the most used element on the planet, everything from pull tabs on soda cans to girders used in construction. Car parts, dog tags, pots and pans, it is everywhere. 95% of aluminium survives recycling, so when you recycle 1,000 can's (or return for deposit in 13 states), it is back on the shelves in the form of 950 new cans in just 6 weeks. As aluminium is a very difficult metal to seprate from other ores such as bauxite, recycling both protects the enviroment by slowing mining, and stabelizing the economy. Its not just a win-win, it can also be quite profitable even with the current low prices for aluminium on the markets.
Q:What method of welding 1mm-3mm aluminium plate? 20
Welding methods almost all kinds of welding methods can be used for welding aluminum and aluminum alloy, but the adaptability of aluminum and aluminum alloy to various welding methods is different, and various welding methods have their respective application. Gas welding and SMAW method, simple equipment, convenient operation. The gas can be used for welding of aluminum plate and casting of high welding quality requirements. Electrode arc welding can be used for repairing welding of aluminium alloy castings. Inert gas shielded welding (TIG or MIG) is the most widely used method for welding aluminum and aluminum alloys. Tungsten and argon arc welding or tungsten arc argon arc welding can be used for aluminum and its alloy sheets. Aluminum and aluminium alloy heavy plates can be made of tungsten helium arc welding, argon helium tungsten gas welding, MIG welding and pulse MIG welding. MIG welding and pulse MIG welding are more and more widely used (argon or argon / helium)Laser welding machine can also be used
Q:How to press multilayer aluminum sheets (aluminum sheet's thickness: 0.2mm) together and keep them inseperate after pressing?
resistance welding usually overlays two pieces together and presses them, heating them to melting state through current, you can try multiple sheets.
Q:6061-T6 can aluminum sheets be bent?
Landlord problem solving, no, I'm with you the same situation, into a batch of 2mm thick black, bending no problem, 3mm shine fold, 90 degrees bend ninety percent off break, I use punch press die bending
Q:calculating ions in Aluminum Nitrate?
OK - first you need the ENTIRE mass of the aluminum nitrate (gram formula mass). You need the correct formula for aluminum nitrate, then add up the atomic masses from the periodic chart. Then, you need to convert 3.99 g of aluminum nitrate to moles of aluminum nitrate. (grams/formula mass = moles) Then, you need to take into account how many moles of nitrate ions are in a mole (look at the correct formula for aluminum nitrate). Then multiply by the number of moles you calculated (moles of ions per molecule x #moles). This would be moles of ions. You need individual ions you would the multiply by 6.02 x 10^23 ions/mole. SO: grams of sample divided by formula mass x #nitrate ions per molecule x (6.023 x 10^23 ions per mole) = # ions

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