Coated Aluminum Coils for Beverage Can Stock

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Loading Port:
Shekou
Payment Terms:
TT OR LC
Min Order Qty:
7 m.t.
Supply Capability:
100000 m.t./month

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1.Structure of Coated Aluminum Coils for Beverage Can Stock

Our coated aluminium coils are widely used in beverage can stock, such as can ends, can lids, can tabs, aluminium easy-can-cover and ring-pull, etc.

We normally use 5052 H19; 5052, H36; 5182 H19; 5182 H48, 5182 H49 as base coils. Based on ordinary aluminum, we add Mn and Mg, so as to increase tensile strength and elongation.

As for coating, we normal coat gold color for lids, red, blue, etc for tabs. We also can adjust coating according to color of customers and offer personalized services.

We use large wave shear, transverse shear and longitudinal cut system so as to meet different specifications of customers.

2. Main Features of Coated Aluminum Coils for Beverage Can Stock

• Light Weight

• High Flatness

• Good Weathering

• Colorful

• Recycling

• Saving Energy

• Rustproof

3. Coated Aluminum Coils for Beverage Can Stock Images

Coated Aluminum Coils for Beverage Can Stock

Coated Aluminum Coils for Beverage Can Stock

Coated Aluminum Coils for Beverage Can Stock

4. Specification of Coated Aluminum Coils for Beverage Can Stock

ALLOY

TEMPER

THICKNESS

WIDTH

COIL OR LENGTH

5052

5182

H19

H36

H48

H49

0.22-0.5mm

500-1600mm

AS PER YOUR REQUIREMENTS

5. FAQ

AWhat about inspections to guarantee quality?

For each order, we will arrange strict inspection for raw materials, inspection during production and inspection for finished goods.

With requirement of customers, we also can arrange the third party inspection.

BWhat about delivery?

We will put order in production schedule after order gets confirmed against copy of TT or L/C. Normally it takes about one month for production. Exact shipment schedule is different based on different sizes and quantity.

CWhat is the MOQ?

5 tons for each size.

D. Where have you exported?

We have exported to many countries. Main markets include South East Asia, Middle East, North America, South America, etc.

 

 

 


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Q:what is aircraft grade aluminum?
Aluminum is never used in it's pure form. It is always used as an alloy - in combination with other metals and substances. The phrase aircraft grade aluminum is a bit misleading because there are a large number of different grades of aluminum used on aircraft - some of them aren't very special at all, but some of the grades are highly specialized, down to the micro-structure of the metal. Different grades of aluminum contain different quantities of other substances may have been forged or wrought in different types of processes. Typically high performance military aircraft will utilize very grade materials. The common characteristics of high grade aluminum alloys are it's ability to withstand heat and fracturing they are also extremely light. When people advertise products like keys made from aircraft grade aluminum it makes me laugh - because it's most likely to be the same grade aluminum they use to make tray stands, certainly not the same grade they use for structural components! Hope this helps!
Q:what is the final temperature of 250g of water whose initial Temperature is 25 C if 80-g of aluminum initially?
Given Data :-- Mass : Aluminium m(a) = 80 g, Water m(w) = 250 g Initial Temperature : Aluminium t₁ = 70 C and Water t₁' = 25 C Final Temperature of both ( aluminium and water ) = T C (assume) Since Aluminium is initially at a temperature higher than that of water, it (aluminium) will lose heat to water . Heat lost by Al = Q = mass of Aluminium x sp.heat capacity of Aluminium x Temp. change = Q = 80 x 0.215 x ( 70 - T ) cal Heat gained by water = Q' = mass of water x sp.heat capacity of water x Temp. change = Q' = 250 x 1 x ( T - 25 ) According to principle of calorimetery . = Heat lost by aluminium = heat gained by water. = 250 x 1 x ( T - 25 ) = 80 x 0.215 x ( 70 - T ) = T = 27.9 C .... ( Rounded to one decimal place )...... Answer Answer .
Q:aluminum vs. steel trailer?
Well, you already know the differences in weight and cost, so I won't address those. Advantages to an aluminum frame are that it will not rust although it may corrode. However, most steel frames now are coated to protect them from the elements and prevent rusting. Or, the steel can be galvanized. So, if you get a steel frame, check for this. Aluminum is a more brittle metal than steel, so some people think that is does not perform as well in a crash. However, there are no horse trailer crash statistics published to prove or disprove this. The flip side is that a steel frame can have hidden rust weakening it and making it perform poorly in a crash. Should something happen to your frame, steel is often reparable, while aluminum sometimes is not and the trailer is totaled. Aluminum is more difficult to weld than steel.
Q:Does aluminium foil promote or stop waves?
BOTH ARE CORRECT.... COVER THE WHOLE WIRELESS MODEM WITH ALUMINUM FOIL AND GROUND IT SHALL BLOCK ALL THE WIRELESS SIGNAL. CONNECT A SMALL PIECE FOIL TO THE WIRELESS MODEM ANTENNA MIGHT INCREASE THE RANGE A BIT SOME TIME BUT USUALLY NOT WORKING WELL.
Q:Why do the layers loose when taking out coil after roll of aluminum 0.14?
After rolling, the most possible reason may be poor deoiling effect. I think, for 0.14mm aluminum coil, the lining sleeve will not be forgotten. After rolling , oil ooze from aluminum layers, and the support of aluminum coil is not enough, leading to coil collapsing. The specific manifestations are that the edges of even round aluminum layers become like water ripple, and that the aluminum coils suddenly become uneven when taking out coil.
Q:aluminum for thermite?
In 35+ years of demonstrating the thermite reaction, I have used fine aluminium powder to quite visible small bits. The proportions don't seem too critical, but try and keep near the amounts represented by the balanced eqtn. The difficult bit is getting the wretched stuff to ignite. With some mixes several strands of magnesium ribbon as fuse still wouldn't get it to ignite. I found a pile of 'ignition powder' at the base of the Mg often helped. There was a good commercial one available in the UK but I often made one up, main ingredients barium peroxide and magnesium powder, about 50/50. Needless to say, ignite with this mix where you won't breathe any nasty fumes. To get a good result, if I didn't use a proper crucible, I shaped one of Al foil about the capacity of 2-3 eggcups. This was put on sand in a big coffee tin, then more sand added to fill round the sides. This would give a good amount of iron. I once made the mistake of rushing in too quickly to get out the red hot iron.... and completely melted the ends of a large pair of Nickel tongs!
Q:why is aluminum oxide used more frequently than silicon carbide as an abrasive?
Cost
Q:If a typical roll of aluminum foil is 12 inches across, what length of aluminum foil would contain 1 mole...?
WHEN IM OUT ON THE SEA WITH ME CREW I LIKE TO THINK THAT PERHAPSY WE CAN LOOT A BARGE FULL 'O THAT WONDROUS MATERIAL YE CALL ALUMINUM AS FER MOLES, THEY CAN BE QUITE THE PESTS AROUND YER GARDEN AND WHAT-NOT
Q:Which companies will use aluminum sheet and coil?
Aluminum sheet coating plant
Q:Calculate the resistance of aluminium cable of length 1o km and diameter 2mm?
Let ρ be the resistivity of the aluminum cable, A the cross sectional area of the cable and l the cable's length. The resistance R of the aluminum cable is now given by: R = ρ·l / A = 2.7·10^-8·(10·10^3) / (π·r²) = 2.7·10^-8·(10·10^3) / (π·(1·10^-3)²) = 85.9 Ω I guess the tricky part is remembering: R = ρ·l / A but when you realize how intuitive this equation is you don't have to memorize it. The resistance R is proportional to the resistivity ρ, so we must have the following in our equation: R = ρ·k , where k is some value governed by the dimensions of the cable! It is logical that the resistance is also proportional to the wires length l. This is logical when you realize that the longer the wire the more obstacles the electrons will have to pass by! Now we have that: R = ρ·l·c , where c is another value governed now by the cross sectional area (only dimensional property left). If we think of the wire as a highway with cars instead of electrons we realize that there is less resistance (higher speed) when the highway has many lanes and is very broad. From this we realize that the greater the cross sectional area the smaller the resistance. R must therefore be inversely proportional to A. We now have: R = ρ·l / A I hope there are no mistakes here :P

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