Aluminum Rolls 2024 for Automotive Spare Parts

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5 m.t.
Supply Capability:
100000 m.t./month

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Item specifice:

Grade: 2000 Series Surface Treatment: Mill Finish Shape: Round
Temper: O-H112 Application: Transportation Tools

Product Description:

1.Structure of Aluminum Rolls 2024 for Automotive Spare Parts

Aluminum Sheets are strengthened and cut from raw materials with different alloys, such as AA5005, AA5052, etc. They are easy for processing in different shapes, good in intensity and can be quickly installed. Aluminium Sheets for Energy Saving Curtain Walls are good in energy saving, weather resistance, fire resistance, easy for maintenance and with many colors.

Aluminium Sheets for Energy Saving Curtain Walls are widely used in construction of metal walls, metal ceilings, car decoration, advertizing panels, etc.

2.Main Features of Aluminum Rolls 2024 for Automotive Spare Parts

•High intensity

•Easy to be processed and shaped

•Weather resistance

•Anti-pollution & environment protection

3. Aluminum Rolls 2024 for Automotive Spare Parts Images

Aluminum Rolls 2024 for Automotive Spare Parts

Aluminum Rolls 2024 for Automotive Spare Parts

Aluminum Rolls 2024 for Automotive Spare Parts

4.Specification of Aluminum Rolls 2024 for Automotive Spare Parts

Alloy Number



H12, H14, H16, H18, H22, H24, H26, H32, HO, F


0.1mm – 500mm


10mm- 2200mm


GB/T3880-2006, ASTM, ISO, EU standard


AWhat about inspections to guarantee quality?

For each order for Aluminum Sheets with Mill Finished Surface AA5XXX, we will arrange strict inspection for raw materials, inspection during production and inspection for finished goods.

With requirement of customers, we also can arrange the third party inspection.

BWhat about delivery?

We will put order for Aluminum Sheets with Mill Finished Surface AA5XXX in production schedule after order gets confirmed against copy of TT or L/C. Normally it takes about one month for production. Exact shipment schedule is different based on different sizes and quantity.

CWhat is the MOQ?

5 tons for each size.

D. Where have you exported aluminium sheets?

We have exported aluminum sheets to many countries. Main markets include South East Asia, Middle East, North America, South America, etc.

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Q:Ship aluminum plate 5What type of aluminum plate does the ship use?
Marine yacht with 5083, with 5456 of inland water on it, domestic Park boat 5052 will be used
Q:Can steel screws be used with aluminium?
Rivets would be best or enameled steel screws could be second choice.
Q:Purchase an aluminum camper or a fiberglass camper?
Aluminum is lighter so it offers economies over the life of the trailer. The Airstream has been built almost as long as I've been around. It is true that the wood does rot And some care is needed to stop the occasional leak. Fiberglass is heaver and has it's own maintenance issues. I've no experience with the Wildwood. What I do know is that motor homes are dirt cheap right now. You might think about taking advantage of the economy and pick-up a motor home at a bargain.
Q:How do I calculate the weight of aluminum sheet? What is the density?
First calculate the density of each aluminum plate, then calculate the volume, then the density is good, the volume is the weight
Q:Tightening small aluminum wires?
Make sure all work is done to code, we had a house with aluminum wiring, it gets hot when a larger load is applied. When selling, the couple who bought it had an inspector come and he said we had to do all this work or they could not get a mortgage. Whatever you do, make sure it is fully up to code, or you will have alot of trouble selling your home one day.
Q:reaction between aluminium and potassium hydroxide in water?
Hi there! So you're given Aluminum metal, which has the oxidation state (almost always) of 3+. In play are: Al 3+ K+ OH- You have KOH(aq) + Al 3+ and they react to form a precipitate, creating Al(OH)3 and the potassium cation disperses into solution. In traditional symbols: 3 KOH (aq) + Al 3+(s) ----- Al(OH)3(s) + 3K+ (aq) That's 3 K+, 3 OH-, and 1 Al 3+. That carries for both sides! NIE would look like: 3 OH- + Al 3+ ----- Al(OH)3 (s) Most instructors don't mind if you leave off (aq) but pretty much all of them care about (s), so make sure you add those phase states! I hope I helped :)
Q:help with aluminium and titanium questions?
1. When exposed to air, pure aluminium rapidly forms a passive oxide layer, alumina, which further inhibits aluminium reactions with other elements. 2. Aluminium can be made stronger by alloying with other elements. One of the most known aluminum alloy is duraluminium, where the principal alloying component is copper. 3. Exactly as aluminium, titanium corrosion resistance is due to its high reactivity with oxygen. When pure titanium is exposed to air it forms a passive titanium dioxide layer on the surfaces exposed which further prohibits other reactions with corrosion agents. 4. The use of titanium in jet engines components is favored by its strength to weight ration, which is unmatched by any other metal. As for the nuclear reactors, its use is preferred because of its superior corrosion resistance associated with fracture toughness and overall durability. 5. Both titanium and aluminium are refined from their respective mined ores - bauxite, for aluminium, ilmenite and rutile for titanium. Basically, these are oxides of the metals. Pure metal has to be reduced from these ores and processes involve use of temperatures up to and sometime exceeding 1000 degrees Celsius, which obviously requires a great consumption of energy, including electricity. Moreover, pure aluminium is obtained in the final processing phase through electrolysis, meaning an electrical current is needed in order to drive the required chemical reactions, thus adding to the electrical consumption. 6. Recycling aluminium from aluminium simply requires the remelting of the metal, eliminating the electrolytic phase that is high electric energy consuming.
Q:Is there aluminum in tin?
No Aluminium (Al) is an element with atomic number 13. Tin (Sn) is another element with atomic number 50
Q:I was told that Aluminum could not be sterilized, is this true?
Sterilization refers to the ability to clean a surface of bacterium. Simply pouring rubbing alcohol on something sterilizes it. Aluminum can be sterilized just as good as any other metal. If it couldn't, would we ship our favorite drinks in cans of it?
Q:student combines 43.1 mL of a 0.279 M aluminum chloride solution with 14.6 mL of a 0.464 M aluminum sulfate (a?
You have to be able to determine the number of moles of Al+3 that each solution contributes to the final solution: 1. aluminum chloride: AlCl3 Multiply the volume (in L) by the molarity to determine the number of moles of each compound dissolved in solution. 0.0431 L x 0.279 M = 0.0120 mol AlCl3 in solution When the AlCl3 in placed in the water, it dissociates to form the following ions: AlCl3 -- Al+3 + 3Cl- So for every one mole of AlCl3 placed in the water, one mole of aluminum ions will dissociate. Therefore, since we have 0.0120 mole of AlCl3 in the solution, that means that the aluminum chloride will contribute 0.0120 Al+3 ions to the final solution. 2. Aluminum sulfate: Al2(SO4)3 Multiply the volume (in L) by the molarity to determine the number of moles of each compound dissolved in solution. 0.0146 L x 0.464 M = 0.00677 mol Al2(SO4)3 in solution When the Al2(SO4)3 in placed in the water, it dissociates to form the following ions: Al2(SO4)3 -- 2Al+3 + 3(SO4)-2 So for every one mole of Al2(SO4)3 placed in the water, two mole of aluminum ions will dissociate. Use the mole ratios of the dissociation reaction to determine the number of moles of Al+3 ions that the aluminum sulfate contributes to the solution. 0.00677 mol Al2(SO4)3 x (2 mol Al+3 ions / 1 mol Al2(SO4)3) = 0.01354 mol Al+3 ions Therefore, the total number of Al+3 ions in solution is the sum: 0.01354 + 0.0120 = 0.02554 mol Al+3 ions The last piece of information needed to determine the concentration of the final solution is the volume of the final solution. Since the two volumes were mixed, the volume of the final solution will be the sum of the two solutions. 0.0431 L + 0.0146 L = 0.0577 L Therefore, to calculate molarity: Molarity = moles of solute / liters of solution Molarity = 0.02554 mol / 0.0577 L = 0.443 M Al+3

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