Aluminium Coil With Best Stocks Price In Our Warehouse

Ref Price:
Loading Port:
Payment Terms:
Min Order Qty:
4 m.t.
Supply Capability:
5000 m.t./month

OKorder Service Pledge

Quality Product

Order On-line Tracking

Timely Delivery

OKorder Service Pledge

Credit Rating

Credit Services

Credit Purchasing

Share to:

Item specifice:

Grade: 6000 Series Surface Treatment: Holographic Impression Shape: Oval
Temper: Half Hard,T351-T651 Application: Seal & Closure Technique: Extruded

Product Description:

1.Structure of Product Description

cold drawn and cold rolled aluminum sheet is widely used in the field of construction field and decoration field, etc.

There are many different grades, such as: 1000 series,6000 series,7000series, 8000 series, etc. The detailed grade are as follows: 1050, 1100,1060,2024, 3003, 3105, 5052,5754,6061,6063,8011, etc.

The temper is include H14, H22, H24, H44,F,etc.

2. Main features of the product

a.Competitive price

c. Shortest service.

3. Image.

Aluminium Coil With Best Stocks Price In Our Warehouse

Aluminium Coil With Best Stocks Price In Our Warehouse

4. Product detailed sizes:

1220mm*2440mm,1219mm*2438mm,1500mm*3000mm, etc.

5. FAQ:

What is the quality standard?

---Usually our standard is GB3880-2006 or others.

What is the width range?

---It is from 300mm to 2500mm, etc.

What is the length range:

---It is from 500mm to 6000mm, etc.

---Normally it is around 2 tons/each size.

How many tons did you export in one year?

Where is your client from?

---Normally it is from bangladesh, fiji, SRI LANKA,uae,Saudi Arabia, 

What is your mainly products?

---Normally they are aluminum sheet,big-5-bar aluminium checkered sheet,small-5-bar aluminium checkered sheet,mirror finish aluminium sheet, aluminum casting coil, etc.



Send a message to us:

Remaining: 4000 characters

- Self introduction

- Required specifications

- Inquire about price/MOQ

Q:Into which compound does aluminium nitrate decompose?
l would say you have mostly aluminum oxide as a product which probably contains some Nitrogen dioxide gas, a second product of the decomposition of aluminum nitrate. If I were you I would not heat nitrate salts as they can explode upon heating. they also need to be kept away from any kind of reducing agent such as powdered metals, or any fuels, reactions can be violent.
Q:How much is the aluminum plate shearing machine?
Guillotine shears. Consult medirect dealAskCan cut 2 millimeters, 1.2 meters wide on the lineChasing the answerJust get a mechanical guillotine, 3*1500Contact me if necessary
Q:Analysis of a Magnesium-Aluminum Alloy?
P_H2 = 0.950 atm (Dalton's Law of partial pressures) n=Pv/RT = (0.950 atm)(0.311 L) / (0.08206 (L*atm)/(mol*K))(302.15 K) n_H2 = 0.011915983 mol Balanced equations: Al + 3HCl -- 3/2H2 + AlCl3 Mg + 2HCl -- H2 + MgCl2 By these equations, we know that every mole of Al will give us 1.5 moles of H2, and every mole of Mg will give 1 mole of H2. We can therefore set up an equation for the mass of Al like this: *Let a = the mass of MAGNESIUM* Al = 0.250 g - a With this equation in mind, we can setup two equations solving for 'n' of each element by dividing by its molar mass and multiplying by the molar ratio: n_Mg = a / 24.30 (1:1 ratio, so we don't have to multiply) -- number of moles of H2 produced by the reaction of Mg (now written as n_H') = a / 24.30 n_Al = (0.250 g - a) / (26.98 g/mol) Because of the molar ratio shown above, we must multiply n_Al by 1.5 in order to get n_H2 produced by the reaction of aluminum, hereafter known as n_H2 Since we know the number of moles produced by the sum of the reactions, we can add these equations together and solve for n_H2. (**note that your value will be different because you have a different volume**) Set up the equation like this: n_H2' + n_H2 = n_H2 = 0.011915983 mol Sub in your individual equations for n_H2' and n_H2: (a/24.3) + 1.5[(0.250-a)/26.98] = 0.011915983 mol Rearrange and solve for a (mass of MAGNESIUM): (26.98a + 9.1125 - 36.45a) / (24.3)(26.98) = 0.011915983 0.011915983 = 9.47a a = 0.137298281 g Once you have your 'a' value, divide it by the total mass (0.250 g) and multiply by 100%. This gives you the percentage of Mg. (0.137298281 g / 0.250 g) * 100% = 54.9193 % Since you want ALUMINUM, you must subtract the percentage of Mg from 100. 100 - 54.9193 = 45.08% So, the mass percentage of aluminum is 45.08%. I hope this is helpful!
Q:What is aluminium plate L2-Y2?
China plastic deformation of pure aluminum grades are 1080, 1080A, 1070, 107000A (L1), 1370, 1060, 1050 (L2), 1050A (L3), 1A50 (LB2), 1350, 1145, 1035 (L4), 1A30 (L4-1), 1100 (L5-1), 1200 (L-5), 1235. Iron and silicon are their major impurities and are increasing by the number of brands.2, Y2: indicates that the material is in a semi hard state
Q:Aluminium or hi-ten bike?
Get an aluminum frame Hi-ten steel is the buzz word for cheap plain steel.
Q:recycling aluminum?
To electrolyse aluminium oxide, it has to be molten. However, the melting point of Al2O3 is extremely high ( 1000°C), and that would make the electrolysis very inefficient. However, Al2O3 dissolves in cryolite at much lower temperatures (lower than 900°C), which makes it a much more viable process.
Q:who knows the ceiling technology of aluminum sheet?
Different materials usually have difference in construction technology. The detailed ceiling construction technology process of aluminum buckle plate:1, snapping line: according to the elevation horizontal line of floor, designed elevation, surrounding ceiling elevation horizontal line, you can find the central point of your room. Then alone the ceiling’s elevation horizontal line, take the central point of your room as focus, you can draw the grading line of keel. 2, install main keel boom: after ensuring the ceiling’s elevation horizontal line and keel’s location line, you can measure the elevation of the below ending of boom, and install the boom processed before. You can use expansion bolt to fix the boom on ceiling. Choose round steel as boom, control the gap of hanging bar under the range of 1200mm.3, install main keel: choose C38 light steel keel as main keel, control the gap under 1200mm. connect it with fitting and boom matched with main keel while installing. 4, install side keel: fix 25×25mm coated keel on the surrounding wall with cement nail according to net height of ceiling, control the cement nail’s gap under 300mm. 5, install sub keel: install the sub keel matched with aluminum buckle plate according to the size of aluminum buckle plate, hang the sub keel on main keel through hanger. When the sub keel needs to be prolonged by several keel, use the adapting piece of sub keel, connect the two ends and fix them after straightening at the same time of hanging the sub keel.
Q:Which statement describes a chemical property of aluminum?
The answer is choice 2. Why? It's the only one that describes a chemical interaction. The other three describe physical properties of aluminum, that is properties that do not involve a change in the chemical identity of aluminum metal. In choices 1, 3, and 4, the aluminum metal remains as aluminum metal. However, in choice 2, the metal reacts and becomes aluminum ion.
Q:What chemically happens when aluminum reacts with anthocyanins?
Two factors affect the color in Hydrangea macrophylla cultivars: soil acidity and the presence of aluminium in the soil. To obtain a blue hydrangea, aluminum must be present in the soil. The pH of the soil should be low (4 - 4.5). In alkaline soil aluminium is tied up. The plants are unable to absorb the existing aluminium and the flowers will not bloom blue. Also, when aluminium in the soil is used up the flower color will be red or pink again. If the soil is watered with aluminium salts aluminium is accumulated in the petals and the color turns blue. Only red and pink colored Hortensis are suitable for the breeding of blue flowers. They contain the dye component delphinidin. At the end of this site you find explanation and the formula:
Q:How many molecules are in 1 square foot of aluminum foil?
Since aluminum foil is an amalgamation of various metals you would first need to know the full chemical breakdown in order to determine how many molecules there are in a square foot of aluminum foil. That said, if your foil was 100% aluminum, you could determine the number of AL atoms by first determining the mass of the foil and dividing by the molecular weight of AL. Multiply that by 6.022 x 10^23 to determine the number of atoms.

1. Manufacturer Overview

Year Established
Annual Output Value
Main Markets
Company Certifications

2. Manufacturer Certificates

a) Certification Name  
Validity Period  

3. Manufacturer Capability

a)Trade Capacity  
Nearest Port
Export Percentage
No.of Employees in Trade Department
Language Spoken:
b)Factory Information  
Factory Size:
No. of Production Lines
Contract Manufacturing
Product Price Range