5000t - 10000t Bolted Mental Maize Silos for Sale

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Loading Port:
Qingdao
Payment Terms:
TT or LC
Min Order Qty:
50 m.t.
Supply Capability:
500000 m.t./month

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Product Description:

 5000t - 10000t Bolted Mental Maize Silos for Sale

 

Product Description

 

Steel Silo Bolt Structure

1. Silo Body

Include the wall plate, column, manhole, roof ladders and so on.

 

(1) wall plate

Our steel is hot galvanized, which makes it durable and weather resistant. Our advanced bolts with spherical washer and the resisting-worn rubber are used to ensure the tightness and using period.

 

(2) Column

 

The column, made by the Z-bar, is used to reinforce the silo body. It is connected by junction panels.

 

(3) Manhole and Roof Ladders

 

There are inspection door and ladders inside and outside the silo body. It is convenient and accessible for any maintenance work.

 

2. Roof

Roof is made up of radiated beam, roof cover board, tension ring, ventilator scoop, roof cap, etc.

 

A whole grain storage system

(the following drawing is designed by our sales, our engineer will finally give a design of your needed grain storage system in CAD format after determination )

 

 

Installation

 

The installation of silos can be carried out by 3 ways.

 

*If the client wants to install silos by themselves, we could offer detailed instruction, and give our quickest response to deal with any question in the process.

*We could also send our engineer to supervise the installation process. The client could find local workers for the installation work and our engineer will help them during the process.

*If the client needs, we could send our installation team for the whole installation issue.

 

(Silo wall plate)

 

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Q:please let our royals do drugs! might mellow them out a little and we won't have to invade china or columbia
ok fine...but let's not give the peeps who control the nuke silos halucinogens
Q:Is it Ok to fix silo with galvanized anchore bolts?
Hi That`s what I would use.
Q:When people call themselves beancounters what does that mean?
Usually accountants.
Q:Why are there different silos?
For different uses and different locations. Here's a web site with more information.
Q:find minimum?
Let V = volume of silo V = volume of hemisphere + volume of cylinder Volume of hemisphere = (2/3)(pi)r^3 Volume of cylinder = (pi)r^2h where r = radius of cylinder = radius of hemisphere h = height of the cylinder Since V = 100, 100 = (2/3)(pi)r^3 + pi(r^2)h and solving for h h = (100/(pi*r^2)) - (2r/3) S = Surface area of silo = surface area of hemisphere + surface area of cylinder Surface area of hemisphere = 2(pi)r^2 Surface area of cylinder = pi(r^2) + 2(pi)rh Therefore, S = 2(pi)r^2 + pi(r^2) + 2(pi)rh since h = (100/(pi*r^2)) - (2r/3) and substituting it in the above equation, S = 2(pi)r^2 + pi(r^2) + 2(pi)r[100/(pi*r^2)) - (2r/3)] Simplifying the above, S = 2(pi)r^2 + [(pi)r^2 + 200/r - 2(pi)r^2/3] S = 2(pi)r^2 + [(1/3)(pi)r^2 + 200/r] Since cost of hemisphere is twice that of the cylinder, then C = cost = 2*2(pi)r^2 + 1*[(1/3)(pi)r^2 + 200/r] C = 4(pi)r^2 + (1/3(pi)r^2 + 200/r C = (13/3)(pi)r^2 + 200/r Differentiating C with respec to r, (dC/dr) = (26/3)(pi)r - 200/r^2 and setting (dC/dr) = 0 and solving for r, (26/3)(pi)r - 200/r^2 = 0 Simplifying the above, 26(pi)r^3 = 600 Solving for r, r = 1.94 meters Now, that r is known, h can be determined by using the above derived formula of h = (100/(pi*r^2)) - (2r/3) Substituting r = 1.94. h = 7.16 meters Dimensions of the silo are: r = 1.94 m h = 7.16 m CHECK: First check: V = (2/3)(pi)(1.94)^3 + pi(1.94)^2(7.16) V = 15.3 + 84.7 = 100 m (this checks with the original condition of the problem that the volume of the silo is fixed at 100 m^3). Second check: Take the second derivative of the original function, i.e., (d^2C/d^2r) = 400/r^3 and since the second derivative is positive (greater than zero), then it confirms that the calculated dimensions for r and h will indeed yield the minimum cost.
Q:How much would it cost to buy/create a nuclear bunker?
With every day pass, our country is getting into more and more trouble. The inflation, unemployment and falling value of dollar are the main concern for our Government but authorities are just sleeping, they don’t want to face the fact. Media is also involve in it, they are force to stop showing the real economic situation to the people. I start getting more concern about my future as well as my family after watching the response of our Government for the people that affected by hurricane Katrina. According to recent studies made by World Bank, the coming crisis will be far worse than initially predicted. So if you're already preparing for the crisis (or haven't started yet) make sure you watch this video at www.familysurvival.tv and discover the 4 BIG issues you'll have to deal with when the crisis hits, and how to solve them fast (before the disaster strikes your town!) without spending $1,000s on overrated items and useless survival books.
Q:In missour abandoned missile silos?
Most okorder.com/
Q:This is my tattoo idea, but it needs to be grammar tweaked?
Since she has personalized it with He, personalize yours. I am her dreamcatcher.
Q:What is a top organizational problem?
it means that the people on top (bosses and the link) are not giving the proper vision to those under them.
Q:Help with area in polar coordinates problem?
interesting. I am going to put the center of the silo at 0,0. This puts the spot where the silo meets the barn wall (and where the goat is tethered) at (10,0) the total length of the rope is 20 pi feet (equal to the circumference of the silo) now the goat wants to get to some spot and it stretches the tether as far as it can go. The cord wraps around the silo for some distance and then stretches out straight for some other distance. The length of rope in contact with the silo we will say is 10 t. The position of the point where the rope starts to lose contact is (10 cos t, 10 sin t) the remaining rope has length (20pi - 10t), and the position of the goat is at (10 cos t - (20pi - 10t) sin t, 10 sin t + (20pi-10 t) cos t) or x = 10 cos t - (20pi - 10t) sin t y = 10 sin t + (20pi-10 t) cos t area = integral of x dy/dt dt = integral of y dx/dt dt dy/dt = 10 cos t - (20pi - 10 t) sin t - 10 cos t = - (20pi - 10 t) sin t A = ∫ (10 cos t - (20pi - 10t) sin t)(10 t - 20pi) sin t dt t = 0 to 2pi ∫ -10(20pi-10t) sin t cos t + (20pi - 10t)^2 sin^2 t) dt lets do this in pieces ∫-10(20pi-10t) sin t cos t integrate by parts u = 20 pi - 10 t dv = sin t cos t du = -10 v = -1/4 cos 2t 10{(20 pi - 10 t) (1/4)cos 2t +10 ∫10/4 cos 2t dt} 10{(20 pi - 10 t) (1/4)cos 2t - 10/8 sin 2t | [0,2pi]} -50 pi ∫ (20pi - 10t)^2 sin^2 t) dt integrate by parts u = (20pi - 10t)^2 dv = sin^2 t du = -20(20pi - 10t) v = 1/2 (t - sin t cos t) 1/2 (t - sin t cos t)(20pi - 10t)^2 | [0,2pi] = 0 +∫10(20pi - 10t)(t-sin t cos t) dt = ∫-10(20pi - 10t) sin t cos t + 10(20pi - 10 t) t dt = -50 pi +100 pi t^2 - 100/3 t^3 -100 pi + 400 pi^2 - 800 / 3 pi^3 But the goat can't get into the silo... - 100 pi -200pi + 400 pi^2 - 800/3 pi^3

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