3mm Anti Slip Embossed Aluminum Checker Plate Sheet

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Shanghai
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TT OR LC
Min Order Qty:
5 m.t.
Supply Capability:
9000 m.t./month

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Item specifice:

Grade: 1000 Series,3000 Series,4000 Series,5000 Series,6000 Series,7000 Series,2000 Series Surface Treatment: Coated,Embossed,Anodized,Polished,Mill Finish,Color Coated,Oxidized,Enameled Wire,Brushed,Printed,Composited,Holographic Impression,Sand Blasted,Powder Coating Shape: Angle,Square,T-Profile,Round,Flat,Rectangular,Oval,Hexagonal
Temper: T3-T8,O-H112,T351-T651,T351-T851,Soft,Half Hard,Hard Application: Liner & Wad,Decorations,Door & Window,Heat Sink,Transportation Tools,Glass Wall,Food,Kitchen Use,Pharmaceutical,Seal & Closure,Insulation Material,Label & Tag

Product Description:

Product Description

 

The brilliant shine of Aluminum Diamond Plate adds sparkle, along with durability. As known as: Aluminum Diamond Plate, Aluminum Tread Plate, Tread Bright, Aluminum Floor Plate, this highly reflective, economical product is widely used in decorative, cosmetic and architectural applications. Having good forming, drilling and welding ability, Aluminum Diamond Plate is easy to fabricate and its raised diamond lug pattern provides good slip resistance.  

3mm Anti Slip Embossed Aluminum Checker Plate Sheet 

Specifications for anti slip aluminum sheet:

 

Alloy No.Thickness  
(mm)
Width 
(mm)
Length 
(mm)
Temper
A1050,A1060, A1070,A11001.0-1020-220020-8000H12,H22,H14,H16,H18, H24,H26,etc
A3003,A3105,A30041.0-1020-220020-8000H14,H18,H24,etc
A5052,A5005,A5083, A57541.0-1020-220020-8000H18,H24,H32,H34,H111,H112 ,etc
A6061,A6082,A60631.0-1020-220020-8000T4,T6,,etc
A80111.0-1020-220020-8000H12,H22,H14,H16,H18,H24,H26, etc

 3mm Anti Slip Embossed Aluminum Checker Plate Sheet

 

Standards:

 

ASTM-B209. EN573-1, GB/T3880.1-2006

 

Quality of material:

 

totally free from defects like white rust, oil patches, roll marks, edge damage, camber, dents, holes, break lines, scratches and free from coil set 

 

Application :

 

Mainly used insigns, billboards, building exterior decoration, bus body, high-rise buildings and factories wall decoration, kitchen sink, lamp, fan leaves, with pieces of electronic, chemical equipment, sheet metal processing parts,     deep drawing or spinning hollowware, welding parts, heat exchangers, bell surface and disk, plate, kitchenware, decorations, reflective devices, ect.

 3mm Anti Slip Embossed Aluminum Checker Plate Sheet

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Q:Where is the difference between the 5052 aluminum plate and the 1060 Aluminum plate?
5052 is aluminium magnesium alloy, 1060 is pure aluminium
Q:Displacement reactions with aluminum?
Aluminium has a protective coating of Aluminium Oxide, this prevents many chemicals reaching the surface. This is because aluminium has a very strong affinity for oxygen and bonds to it with extremely strong bonds. It can be removed by dipping it carefully into a solution of Mercury (II) Chloride.
Q:reaction between aluminium and potassium hydroxide in water?
So convert 27,8 g iron to moles, and convert that to a mass of aluminium 2. 3 CuNO3 + Fe3+ -- Fe(NO3)3 + 3 Cu+ 3. 2 Fe3+ + 3 O2- --- Fe2O3 So convert Fe2O3 from 20,8 grams to moles. Multiply this answer by two. Convert to a mass of Fe3+ 4. H2SO4 + 2 KOH -- K2SO4 + 2 H2O again, 150 grams of H2SO4 to moles, then convert that amount to an amount of mass of K2SO4 5. Na2CO3 + 2 H3O+ + Cl- --- CO2 + 3 H2O + NaCl
Q:How many molecules are in 1 square foot of aluminum foil?
Since aluminum foil is an amalgamation of various metals you would first need to know the full chemical breakdown in order to determine how many molecules there are in a square foot of aluminum foil. That said, if your foil was 100% aluminum, you could determine the number of AL atoms by first determining the mass of the foil and dividing by the molecular weight of AL. Multiply that by 6.022 x 10^23 to determine the number of atoms.
Q:Would Lava Melt an Aluminum Can?
Aluminum cans melt at about 1220 F. Lava is about 1300F to 2400F. The can would melt into the lava.
Q:How do you calculate the price and weight of aluminum sheet?
The material of aluminum plate is divided into many grades100110021003 and so on, each price is not the sameAccording to the smoothness after processing, smoothness and so on, there are larger come and goI remember last year's 2.5 thick 1001 aluminum plate cost price is about 230 square meters
Q:Has anyone heard of Lydney Aluminum?
Lydney Aluminum, I don't think that I have heard of them in the boating industry. T.
Q:Why is aluminum preferred over iron-based alloys in the aerospace and?
Because it's lighter with about the same strength as iron alloys
Q:student combines 43.1 mL of a 0.279 M aluminum chloride solution with 14.6 mL of a 0.464 M aluminum sulfate (a?
You have to be able to determine the number of moles of Al+3 that each solution contributes to the final solution: 1. aluminum chloride: AlCl3 Multiply the volume (in L) by the molarity to determine the number of moles of each compound dissolved in solution. 0.0431 L x 0.279 M = 0.0120 mol AlCl3 in solution When the AlCl3 in placed in the water, it dissociates to form the following ions: AlCl3 -- Al+3 + 3Cl- So for every one mole of AlCl3 placed in the water, one mole of aluminum ions will dissociate. Therefore, since we have 0.0120 mole of AlCl3 in the solution, that means that the aluminum chloride will contribute 0.0120 Al+3 ions to the final solution. 2. Aluminum sulfate: Al2(SO4)3 Multiply the volume (in L) by the molarity to determine the number of moles of each compound dissolved in solution. 0.0146 L x 0.464 M = 0.00677 mol Al2(SO4)3 in solution When the Al2(SO4)3 in placed in the water, it dissociates to form the following ions: Al2(SO4)3 -- 2Al+3 + 3(SO4)-2 So for every one mole of Al2(SO4)3 placed in the water, two mole of aluminum ions will dissociate. Use the mole ratios of the dissociation reaction to determine the number of moles of Al+3 ions that the aluminum sulfate contributes to the solution. 0.00677 mol Al2(SO4)3 x (2 mol Al+3 ions / 1 mol Al2(SO4)3) = 0.01354 mol Al+3 ions Therefore, the total number of Al+3 ions in solution is the sum: 0.01354 + 0.0120 = 0.02554 mol Al+3 ions The last piece of information needed to determine the concentration of the final solution is the volume of the final solution. Since the two volumes were mixed, the volume of the final solution will be the sum of the two solutions. 0.0431 L + 0.0146 L = 0.0577 L Therefore, to calculate molarity: Molarity = moles of solute / liters of solution Molarity = 0.02554 mol / 0.0577 L = 0.443 M Al+3
Q:Strongest Aluminum Stem?
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