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FAQ

The Operation Room culture was particularly complex because it was organized into silos?I googled the definition but the definition i'm getting does not fit in here at all..thanks for the help!!

It means there are separate vertically organized groups within the organization. This results in the right hand not knowing what the left hand is doing.

A silo(base not included) is to be constructed in teh form of a cylinder with a hemisphere on top. The cost of the construction per square unit of surface area is twice as great for the hemisphere as it is for the cylindrical sidewall. Determine the dimensions to be used if the volume is fixed and the cost of the construction is to be kept at a minimum. Neglect the thickness of the Silo and the waste in construction. I got r=3v/8pi to the 1/3

The volume of the hemisphere is 2/3*pi*r^3, and the volume of the cylinder is pi*r^2*h. 2/3*pi*r^3+pi*r^2*h=V. pi*r^2*h=V-2/3*pi*r^3. h=V/(pi*r^2)-2/3*r. The lateral surface area of the hemisphere is 2*pi*r^2, and the lateral surface area of the cylinder is 2*pi*r*h. A=2*pi*r^2+2*pi*r*h. A=2*pi*r^2+2*pi*r(V/(pi*r^2)-2/3*r). A=2*pi*r^2+2*V/r-4/3*pi*r^2. dA/dr=4*pi*r-2*V/r^2-8/3*pi*r. dA/dr=4/3*pi*r-2*V/r^2. 4/3*pi*r-2*V/r^2=0. 4/3*pi*r=2*V/r^2. 4/3*pi*r^3=2*V. r^3=3/2*V/pi. r=(3V/(2pi))^(1/3). I'm too lazy to figure out the height in terms of V. It would be really nice if they specified what the fixed volume was!

It's for a display at my job.... I just want the front of the classic barn look.... any ideas on how i can do this?? Also I want to make a couple of silos to go with it any suggestions on this would be great... Thanks!

Make it from 1 x 3s or lumber according to the size (width) you need. The attch some 1 x 4s to the back to hold it together. Paint it barn red. Then paint some other boards white for the trim. Fo silos, cut 2 pieces of plywood to the diameter you want. For each silo, use firring strips or 2 x 4s (depending on how sturdy you want it) cut to the height you want. Place at least 12-16 around the outer edge of the pieces of plywood and screw or nail together.

They are the two little gay penguins from the New York Zoo, that were together for over six years (I have no idea how long that is in human years). They were such a good couple the keepers gave them an extra egg. And they raise a chick that would have mostly liked died as an egg, and their kid is named Tango. I understand some chic, named Scrappy, stole Silo away in 2005, but it was short lived. They were together for six year, and the subject of the story, quot;And Tango makes Three.quot;Are Roy and Silo back together again?

i okorder /

n be stored in the silo? (use the value 3.14 for pie, round anwser to the nearest cubic foot.

Volume for a Cylindrical Shape is V = pi radius^2 height In this case V = 3.14 x 7.5^2 x 30 = 5299 ft^3

I heard that in the movie quot;The Day Afterquot; (1982).

It means the producers were too cheap to hire technical consultants that new wtf they were talking about!

A grain silo consists of a cylindrical main section and a hemispherical roof. The cylindrical part is 30 ft tall. Express the total volume of the silo (including the part inside the roof section) as a function of the radius of the silo.V(r)=

Not enough information,need to know the diameter

Suppose a cow is tied to a cylindrical silo of radius 2 with a rope which is long enough to go exactly halfway around the silo, so length of rope = 2 pi.what is the total area the cow can reach?

The answer appears to be (10/3) π?. This involved a semicircular region of radius 2π, plus two axe-blade shaped regions, each of area (2/3) π?. Justification follows. Imagine the silo to be a circle of radius 2 centered at (0,2) on the y-axis, so that it passes through the origin O. Let the cow be tethered at O. Then the cow can access a semicircular region in the third and fourth quadrants of radius 2π, i.e. area 2 π?. In the first quadrant, the region accessible to the cow is swept by the rope when it follows the arc of the silo through an angle θ, where 0 ≤ θ ≤ π, and then extends tangentially to a length of 2 (π - θ). As θ increases by an infinitesimal amount dθ, the rope covers a region approximable by an isosceles triangle with two arms of length 2 (π - θ), with an angle dθ between them. The approximation becomes exact as dθ → 0. This region has area ? [2 (π - θ)]? dθ = 2 (π - θ)? dθ. Integrating this as θ varies from 0 to π gives us (2/3) π?, the area accessible to the cow in the first quadrant. This is also the area accessible in the second quadrant. Adding the areas of the three regions, we get 2 π? + 2 (2/3) π? = (10/3) π?.